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NCERT Solutions for class 11 Maths | Chapter 10 - Straight Lines

(1) Equation (3a – 2b)x2 + (c –2a)y2 + 2hxy = 0 represents pair of straight lines which are perpendicular to each other then (a – b) is equal to
[A] b + c
[B] b – c
[C] c – b
[D] 2c
Answer: b – c
(2) The straight lines of the family x(a+b) + y (a-b) = 2a (a and b being parameters) are
[A] Not concurrent
[B] Concurrent at (1, -1)
[C] Concurrent at (1, 1)
[D] None of these
Answer: Concurrent at (1, 1)

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(3) If the angle between the two straight lines represented by 2x2+ 5xy+ 3y2+7y+4= 0 is tan–1 m then m equals to
[A] 1/5
[B] 1
[C] 7/5
[D] 7
Answer: 1/5
(4) If the sum of the distances of a point from two perpendicular lines in a plane is 1, then its locus is
[A] Square
[B] A circle
[C] straight line
[D] Two intersecting lines
Answer: Square
(5) ax + by + c = 0 represents a line parallel to x–axis if
[A] a = 0, b = 0
[B] a = 0, b ≠ 0
[C] a ≠ 0, b = 0
[D] c = 0
Answer: a = 0, b ≠ 0
(6) If the line y = mx meets the lines x + 2y – 1= 0 and 2x – y + 3 = 0 at the same point, then m is equal to
[A] 1
[B] -1
[C] 2
[D] -2
Answer: -1
(7) If a, b, c are in A.P. then line 2ax + 3by + 3c = 0 always passes through fixed point
[A] (2, –2)
[B] (3/2, 2)
[C] (3/2, –2)
[D] None of these
Answer: (3/2, –2)
(8) The locus of the mid-point of the portion intercepted between the axes by the line x cos a + y sin a = p, where p is a constant is
[A] x2 + y2 = 4p2
[B] 1/x2+1/y2=4/p2
[C] x² + y² = 4/p2
[D] 1/x2+1/y2=2/p2
Answer: 1/x2+1/y2=4/p2
(9) Points on the line x + y = 4 that lie at a unit distance from the line 4x+ 3y–10=0 are
[A] (3, 1) and (–7, 11)
[B] (–3, 7) and (2, 2)
[C] (–3, 7) and (–7, 11)
[D] none of these.
Answer: (3, 1) and (–7, 11)
(10) If one vertex of an equilateral triangle is at (1, –2) and the base is x + y + 2 = 0, then the length of each side is
[A] √3/2
[B] √2/3
[C] 2/3
[D] 3/2
Answer: √2/3
(11) The equation of the line through (3, 4) and parallel to the line y =3x +5 is
[A] 3x – y – 5 =0
[B] 3x + y – 5 = 0
[C] 3x + y + 5 = 0
[D] 3x – y + 5 = 0
Answer: 3x – y – 5 =0
(12) The incentre of the triangle formed by the lines y = |x| and y = 1 is
[A] (0, 2 – √2)
[B] (2 –√2, 0)
[C] (2 +√2, 0)
[D] (0, 2 +√2 )
Answer: (0, 2 – √2)
(13) The quation of the line joining the points (– 1, 3) and (4, – 2) is
[A] x + y – 1 =0
[B] x + y +1 =0
[C] x + y +2 =0
[D] x + y – 2 =0
Answer: x + y – 2 =0
(14) The area of the quadrilateral formed by y = 1 – x, y = 2 – x and the coordinate axes is
[A] 1
[B] 2
[C] 3/2
[D] None of these
Answer: 3/2
(15) The quadratic equation whose roots are the x and y intercepts of the line passing through (1, 1) and making a triangle of area A with axes is
[A] x2 + Ax + 2A = 0
[B] x2 – 2Ax +2A = 0
[C] x2 – Ax + 2A = 0
[D] None of these
Answer: x2 – 2Ax +2A = 0
(16) Locus of the point of intersection of lines x cosa+ y sin α = a and x sin α – y cos α =a is
[A] x2 + y2 =a2
[B] x2 + y2 = 2a2
[C] x2 + y2 + 2x + 2y = a2
[D] None of these
Answer: x2 + y2 = 2a2
(17) The equation of the line through (3, 4) and parallel to the line y =3x +5 is
[A] 3x – y – 5 =0
[B] 3x + y – 5 = 0
[C] 3x + y + 5 = 0
[D] 3x – y + 5 = 0
Answer: 3x – y – 5 =0
(18) The quation of the line joining the points (– 1, 3) and (4, – 2) is
[A] x + y – 1 =0
[B] x + y +1 =0
[C] x + y +2 =0
[D] x + y – 2 =0
Answer: x + y – 2 =0
(19) The equation of straight line which passes through the point (1, 2) and makes an angle cos–1(-1/3)with the x– axis is
[A] (a)
[B] (b)
[C] (c)
[D] (d)
Answer: (a)
(20) The member of the family of lines ( p +q)x + (2p +q)y = p + 2q, where p≠0, q≠0, pass through the point
[A] (3, – 1)
[B] (– 3 ,1)
[C] (1, 1)
[D] None of these
Answer: (3, – 1)

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