(1)
Z = 6x + 21 y, subject to x + 2y ≥ 3, x + 4y ≥ 4, 3x + y ≥ 3, x ≥ 0, y ≥ 0. The minimum value of Z occurs at
Answer: (2, 7/2)
Answer: (2, 7/2)
Answer: 95 at (2, 3)
Answer: 36 at (0, 6)
Answer: 60 at (4, 2)
Answer: 600
Answer: function to be obtimized
Answer: (5, 0)
Answer: 59 at (9/2, 5/2)
Answer: None of these
Answer: Feasible solution
Answer: (7/2, 9/4)
Answer: 37 at (4, 5)
Answer: Have solution for positive x and y
Answer: Vertex point of the boundary of the feasible region
Answer: All of the given constraints
Answer: -17
Answer: 140
Answer: 16 at (2, 1)
Column A | Column B |
Maximum of Z | 325 |
Answer: The quantity in column B is greater
Answer: (0, 8)