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NCERT Solutions for class 12 Maths | Chapter 2 - Inverse Trigonometric Functions

(1) tan-1 (√3) + sec-1 (-2) – cosec-1 (2/√3)
[A] 5/π
[B] 2π/3
[C] π/3
[D] 0
Answer: 0
(2) The principle value of sin-1(sin2π/3)is
[A] 2π/3
[B] π/3
[C] -π/6
[D] π/6
Answer: π/3

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(3) Algebraic expression for sin (cot-1 x) is
[A] 1/1+x2
[B]
[C]
[D] None of these
Answer:
(4) cos-1(cos7π/6) is equal to
[A] 7π/6
[B] 5π/6
[C] π/3
[D] π/6
Answer: 5π/6
(5) cosec-1(2)
[A] π/6
[B] 2π/3
[C] 5π/6
[D] 0
Answer: π/6
(6) If 6 sin-1 (x² – 6x + 8.5) = π, then x is equal to
[A] 1
[B] 2
[C] 3
[D] 8
Answer: 2
(7) tan-1 √3 – sec-1(-2)
[A] π
[B] –π/3, 0
[C] π/3
[D] 2π/3
Answer: –π/3, 0
(8) sin(sec-1 x + cosec-1x) =
[A] 1
[B] -1
[C] π/2
[D] π/3
Answer: 1
(9) sin-1 (1 – x) – 2 sin-1 x = π/2 then x = ?
[A] 0, 1/2
[B] 1, 1/2
[C] 1/2
[D] 0
Answer: 0
(10) The value of x for which sin |cot-1(1 – x)| = cos (tan-1 x) is
[A] 2/1
[B] 1
[C] 0
[D] 1/2
Answer: 1/2
(11) Simplified form of cos-1 (4x3 – 3x)
[A] 3 sin-1x
[B] 3 cos-1x
[C] π – 3 sin-1x
[D] None of these
Answer: 3 cos-1x
(12) 4 tan-1 15 – tan-1 1/239
[A] π
[B] π/2
[C] π/3
[D] π/4
Answer: π/4
(13) Principal value of sin-1(1√2)
[A] π/4
[B] 3π/4
[C] 5π/4
[D] None of these
Answer: π/4
(14) The principal value of cosec-1 (-2) is
[A] –2π/3
[B] π/6
[C] 2π/3
[D] –π/6
Answer: –π/6
(15) Which of the following is the principal value branch of cos-1 x?
[A] [−π/2, π/2]
[B] (0, π)
[C] (0, π)
[D] (0, π) – {π/2}
Answer: (0, π)
(16) If 3 tan-1 x + cot-1 x = π, then x equals
[A] 0
[B] 1
[C] -1
[D] 1/2
Answer: 1
(17) The domain of the function cos-1 (2x – 1) is
[A] [0, 1]
[B] [-1, 1]
[C] [-1, -1]
[D] [0, π]
Answer: [0, 1]
(18) If tan-1 x + tan-1 y = 4π5 then cot-1 x + cot-1 y equals
[A] π/5
[B] 2π/5
[C] 3π/5
[D] π
Answer: π/5
(19) If cos-1 α + cos-1 β + cos-1 γ = 3π, then α(β + γ) + β (γ + α) + γ(α + β) equals
[A] 0
[B] 1
[C] 6
[D] 12
Answer: 6
(20) If cos-1 x > sin-1 x, then
[A] 1/√2 < x ≤ 1
[B] 0 ≤ x < 1/√2
[C] -1 ≤ x < 1/√2
[D] x > 0
Answer: 0 ≤ x < 1/√2

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