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NCERT Solutions for class 12 Maths | Chapter 8 - Application of Integrals

(1) Area of the ellipse is
[A] 4πab sq.units
[B] 2πab sq.units
[C] πab sq.units
[D] πab/2 sq.units
Answer: πab sq.units
(2) The area bounded by the curve 2x2 + y2 = 2 is
[A] π sq. units
[B] √2π sq. units
[C] π/2 sq. units
[D] 2π sq. units
Answer: √2π sq. units

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(3) The area of the ellipse is
[A] 6π sq. units
[B] π(a2+b2)/4 sq. units
[C] p(a + b) sq. units
[D] none of these
Answer: none of these
(4) If y = 2 sin x + sin 2x for 0 ≤ x ≤ 2π, then the area enclosed by the curve and x-axis is
[A] 9/2 sq. units
[B] 8 sq. units
[C] 12 sq. units
[D] 4 sq. units
Answer: 12 sq. units
(5) Area of the region between the curves x2 + y2 = π2, y = sin x and y-axis in first quadrant is
[A] sq. units
[B] sq. units
[C] sq. units
[D] sq. units
Answer: sq. units
(6) The area included between the curves x2 = 4by and y2 = 4ax
[A] 16ab sq. units
[B] 16ab/3 sq. units
[C] 4ab sq. units
[D] 16πab sq. units
Answer: 16ab/3 sq. units
(7) Find the area enclosed by the parabola 4y = 3x2 and the line 2y = 3x + 12.
[A] 27 sq. units
[B] 28 sq. units
[C] 54 sq. units
[D] 30 sq. units
Answer: 27 sq. units
(8) The area lying above x-axis and included between the circle x2 + y2 = 8x and inside of parabola y2 = 4x is
[A] 1/3 (2 + 3π) sq. units
[B] 2/3 (4 + 3π) sq. units
[C] (6 + 3π) sq. units
[D] 4/3 (8 + 3π) sq. units
Answer: 4/3 (8 + 3π) sq. units
(9) The area of smaller portion bounded by |y| = -x + 1 and y2 = 4x is
[A] 1 sq. units
[B] 2 sq. units
[C] 3 sq. units
[D] none of these
Answer: none of these
(10) The area bounded by the line y = 2x – 2, y = -x and x-axis is given by
[A] 9/2 sq. units
[B] 43/6 sq. units
[C] 35/6 sq. units
[D] None of these
Answer: None of these
(11) The area bounded by the lines y = |x – 1| and y = 3 – |x| is
[A] 2 sq. units
[B] 3 sq. units
[C] 4 sq. units
[D] 6 sq. units
Answer: 4 sq. units
(12) Area bounded by the lines y = |x| and y = 1 – |x – 1| is equal to
[A] 4 sq. units
[B] 6 sq. units
[C] 2 sq. units
[D] 8 sq. units
Answer: 4 sq. units
(13) The ratio in which the x-axis divides the area of the region bounded by the curves y = x2 – 4x and y = 2x – x2
[A] 4 : 23
[B] 4 : 27
[C] 4 : 19
[D] none of these
Answer: 4 : 23
(14) The area enclosed by the curve y = √x and x = -√y , the circle x2 + y2 = 2 above the x-axis is
[A] π/4 sq. units
[B] 3π/2 sq. units
[C] π sq. units
[D] π/2 sq. units
Answer: π/2 sq. units
(15) The area enclosed between the graph of y = x3 and the lines x = 0, y = 1, y = 8 is
[A] 45/4
[B] 14
[C] 7
[D] none of these
Answer: 45/4
(16) The area bounded by the curve x2 = 4y = 4y + 4 and line 3x + 4y = 0 is
[A] 0 sq. units
[B] 125/8 sq. units
[C] 125/16 sq. units
[D] 125/24 sq. units
Answer: 125/24 sq. units
(17) The area bounded by y= is
[A] 4/3 sq. units
[B] 13/2 sq. units
[C] 12/5 sq. units
[D] 42/5 sq. units
Answer: 4/3 sq. units
(18) The area bounded by the curves x + 2y2 = 0 and x + 3y2 = 1 is
[A] 1 sq. units
[B] 1/3 sq. units
[C] 2/3 sq. units
[D] 4/3 sq. units
Answer: 4/3 sq. units
(19) The area bounded by the lines y = 4x + 5, y = 5 – x and 4y = x + 5 is
[A] 15/2 sq. units
[B] 92 sq. units
[C] 13/2 sq. units
[D] None of these
Answer: 15/2 sq. units
(20) The area enclosed by the parabola y2 = 2x and tangents through the point (-2, 0) is
[A] 3 sq. units
[B] 4 sq. units
[C] 4/3 sq. units
[D] 8/3 sq. units
Answer: 8/3 sq. units

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