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Free download in PDF Chemical Bonding Objective Type Questions & Answers for competitive exams. These short objective type questions with answers are very important for competitive exams like IIT-JEE, NEET, AIIMS, JIPMER etc. These short solved questions or quizzes are provided by Gkseries.
(21)
Among the following isostructural compounds, which one has highest lattice energy ?
[A]
LiCl
[B]
MgO
[C]
NaCl
[D]
LiF
(22)
A bonded molecule MX3 is T-shaped. The number of non-bonding pairs of electrons is :
[A]
0
[B]
2
[C]
1
[D]
Can be predicted only if atomic number of M is known
(23)
In a chemical change from PCl3 −−−→PCl5 the hybrid state of P changes from:
[A]
sp2 to sp3
[B]
sp3 to sp2
[C]
sp3 to sp3d
[D]
sp3 to dsp
(24)
The geometrical arrangement and shape of I−3 are respectively
[A]
Trigonal bipyramidal geometry, linear shape
[B]
Hexagonal structure, linear shape
[C]
Triangular planar geometry, triangular shape
[D]
Tetrahedral geometry, pyramidal shape
Answer: Trigonal bipyramidal geometry, linear shape
(25)
Which molecules/ions are most paramagnetic?
[A]
B2
[B]
C2
[C]
O+2
[D]
O−2
(26)
Which has linear shape but not sp hibridisation ?
[A]
XeF2
[B]
I−3
[C]
CO2
[D]
Both 1 and 2
(27)
Which of the following structure is most expected for the molecule XeOF4 ?
[A]
Tetrahedral
[B]
Square pyramid
[C]
Square planar
[D]
Octahedral
(28)
Which is mismatched regarding the shape ?
[A]
XeF4 = Square planar
[B]
XeOF4 = Square Pyramidal
[C]
XeF6 = Distorted Octahedral
[D]
XeO3 = Bent Shape
Answer: XeO3 = Bent Shape
(29)
The isostere pair is
[A]
CO2 and N2O
[B]
CO and N2
[C]
O2 and NO2
[D]
Both (1) and (2)
(30)
Select the correct order of solubility (in water) from the following:
[A]
SrSO4 < CaSO4 < MgSO4 < BeSO4
[B]
NaF < KF < RbF < CsF
[C]
Ba(OH)2 > SR(OH)2 > Ca(OH)2 > Mg(OH)2
[D]
All of these
31
Which of the following has largest bond angle.
[A]
H2O
[B]
F2O
[C]
Cl2O
[D]
H2S
32
Amongst H2O, H2S, H2Se and H2Te the one with highest boiling point is:
[A]
H2O because of H-bonding
[B]
H2Te because of higher molecular weight
[C]
H2S because of H-bonding
[D]
H2Se because of lower molecular weight
Answer: H2O because of H-bonding
33
Which of the following are isoelectronic and isostructural?
NO−3, CO-23, ClO−3, SO3
[A]
NO−3, CO-23
[B]
SO3, NO−3
[C]
ClO−3, CO-23
[D]
CO-23, ClO−3
34
Which of the following exhibits H-bonding?
[A]
CH4
[B]
H2Se
[C]
N2H2
[D]
H2S
35
Which has highest bond angle ?
[A]
NH3
[B]
H2O
[C]
H2S
[D]
PH3
36
Which has highest bond energy ?
[A]
CO
[B]
CO+
[C]
N2
[D]
N+2
37
which is the incorrect about bond angles ?
[A]
NH3 > NF3
[B]
NF3 > PF3
[C]
NH3 > PH3
[D]
NH3 > H2O
38
The types of hybrid orbitals of nitrogen in NO2+, NO3- and NH4+ respectively are expected to be
[A]
sp, sp3 and sp2
[B]
sp, sp2 and sp3
[C]
sp2, sp and sp3
[D]
sp2, sp3 and sp
39
Among LiCl, BeCl2, BCl3 and CCl4, the covalent bond character varies as
[A]
LiCl < BeCl2 > BCl3 > CCl4
[B]
LiCl > BeCl2 < BCl3 < CCl4
[C]
LiCl < BeCl2 < BCl3 < CCl4
[D]
LiCl > BeCl2 > BCl3 > CCl4
Answer: LiCl < BeCl2 < BCl3 < CCl4
40
Which of the following statement is not correct from the view point of molecular orbital theory ?
[A]
Be2 is not a stable molecule
[B]
He2 is not a stable but He2+ is expected to exist
[C]
Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period
[D]
The order of energies of molecular orbitals in N2 molecule is 2s < *2s < 2pz < (2px=2py) < (*2px=*2py) < *2pz
Answer: The order of energies of molecular orbitals in N2 molecule is 2s < *2s < 2pz < (2px=2py) < (*2px=*2py) < *2pz
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