(2/13) of 715 + (4/11) of 7150 = ? × 2 + 122
A.1357
B.1562
C.1283
D.1479
E. None of these
Sol:
(2/13) of 715 + (4/11) of 7150 = 2x + 122
(2/13) * 715 + (4/11) * 7150 = 2x + 122
110 + 2600 – 144 = 2x
2566 = 2x
x = 2566 / 2 = 1283
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