Q. 36, 38, (5P + 3Q), 177, 434, 1185 Find the minimum possible value of Q, where P and Q are positive integers.
A.11
B.16
C.3
D.1
E. None of these
Ans: 1
Sol:
36 x 0.5 + 20 = 38
38 x 1 + 40 = 78
78 x 1.5 + 60 = 177
177 x 2 + 80 = 434
434 x 2.5 + 100 = 1185
So,
5P + 3Q = 78
P = (78 – 3Q)/5
When P is maximum then Q is minimum.
On putting Q = 1, P = 15
So, required value = 1
Hence answer is option D
