| Question | Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son? | |
| Type | multiple_choice | |
| Option | 34, 9 | correct |
| Option | 33, 7 | incorrect |
| Option | 35, 5 | incorrect |
| Option | 36, 6 | incorrect |
Let age of son 4 years ago be = X
So, age of man 4 years ago would be = 6X
As per question after 16 years;
2* age of son = age of man
2(X + 4 +16) = (6X + 4 + 16)
2X +40 = 6X + 20
2X – 6X = 20 – 40
– 4X = – 20
X = 5 years
∴Present age of son = 5 + 4= 9 years
Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years
Solution 2:
Apply formula; A’s (man) present age
= 9 years
