| Question | The sum of the ages of father and his son is 44 years. If 6 years after the father will be 3 times as old as his son, what are their present ages? | |
| Type | multiple_choice | |
| Option | 36, 8 | correct |
| Option | 38, 6 | incorrect |
| Option | 35, 9 | incorrect |
| Option | 37, 7 | incorrect |
As per question, after 6 years;
3(X+6) = (44 – X) +6
3X +18 = 50 – X
4X = 50 – 18
4X = 32
X = 8 years
∴Present age of son = 8 years
And, present of father = 44 – 8 = 36 years
Solution 2;
