![A man 1.5 meter tall is 30√3 meter away from a building. When he sees the top of building the angle of elevation is 30°. Find the height of the building?](https://www.gkseries.com/blog/wp-content/uploads/2023/07/A-man-1.5-meter-tall-is-30√3-meter-away-from-a-building.-When-he-sees-the-top-of-building-the-angle-of-elevation-is-30°.-Find-the-height-of-the-building.jpg)
Question | A man 1.5 meter tall is 30√3 meter away from a building. When he sees the top of building the angle of elevation is 30°. Find the height of the building? | |
Type | multiple_choice | |
Option | 31.5m | correct |
Option | 30 m | incorrect |
Option | 53.4m | incorrect |
Option | 48 m | incorrect |
![](https://www.gkseries.com/blog/wp-content/uploads/2023/07/image-108.png)
Let AD be the man and BE the building.
Now draw a line DC so that DC is perpendicular to BE.
Now, BC = AD = 1.5 m
And, DC = AB = 30√3 m
![](https://www.gkseries.com/blog/wp-content/uploads/2023/07/image-109.png)
Now, Height of building, BE = BC + EC
= 1.5 + 30 = 31.5 m (Option A)