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Question | Find the average of first 5 consecutive even numbers starting from 2 to 10, where the last even number is 10. | |
Type | multiple_choice | |
Option | 1 | incorrect |
Option | 6 | correct |
Option | 2 | incorrect |
Option | 8 | incorrect |
Solution | The average of first n consecutive even numbers starting from 2 to X, where the last even number is X, is given by: = (X+2)/2 Here, X=10 So, the required average = (10+2)/2 = 12/2 =6 |