A block of mass 10 kg rests on a horizontal floor. The acceleration due to gravity is 9.81 m/s2. The coefficient of static friction between

Q. A block of mass 10 kg rests on a horizontal floor. The acceleration due to gravity is 9.81 m/s². The coefficient of static friction between the floor and the block is 0.2. A horizontal force of 10 N is applied on the block as shown in the figure. The magnitude of force of friction (in N) on the block is         

Sol:

W=mg=10×9.81=98.1N
Normal force, N N=W=98.1N
Now, maximum value of static friction force
=μ_sN=0.2×98.1=19.62N
∵ Applied force is less than static friction force,so friction force will be same as applied force. Hence, Friction force = 10 N