![A train is running with a speed of (2X - 90) Km/hr while a car is running with a speed of (Y + 30) Km/hr](https://www.gkseries.com/blog/wp-content/uploads/2024/02/A-train-is-running-with-a-speed-of-2X-90-Km-hr-while-a-car-is-running-with-a-speed-of-Y-30-Km-hr.jpg)
Q. A train is running with a speed of (2X – 90) Km/hr while a car is running with a speed of (Y + 30) Km/hr. If the speed of the train had been equal to that of a car, then it would take 2 hours less to cover 180 km. If the speed of the car had been equal to that of the train, then it would take 3 hours more to cover 270 km. Find the difference between the speed of a bike and a car.
A. 40km/hr
B. 60km/hr
C. 80km/hr
D. 45km/hr
E. Cannot be determined.
Sol:
According to the question,
{180/(2x – 90)} – {180/(y + 30)} = 2
{90/(2x – 90)} – {90/(y +30)} = 1 — (1)
Also, {270/ (2x – 90)} – {270/(y +30)} = 3
(90/ (2x – 90)} – {90/(y + 30)} =1 — (2)
Since both equations are the same.
Therefore, the required difference cannot be determined