A person distributed Rs.75000 among three persons P, Q, and R such that P alone get Rs.15000 less than what Q and R together got. If the amount received by Q is 80% of that of R, then what percent of the total amount is given to person P?
a) 60%
b) 50%
c) 30%
d) 45%
e) 40%
Sol:
Let the amount received by Q and R is ‘4x’ and
‘5x’ respectively.
Amount received by P = (4x + 5x) – 15000 = (9x
– 15000)
According to the question:
4x + 5x + (9x – 15000) = 75000
18x = 90000
x = 5000
Total amount received by P = 9x – 15000 =
Rs.30000
Required percent = (30000/75000) * 100 = 40%
