Q) I. 15×2 – 46x + 32 = 0 II. 3y2 – 17y + 24 = 0
a) x> y
b) y> x
c) x ≥ y
d) x ≤ y
e) x = y or relation cannot be established
Sol:
I.
15×2 – 46x + 32 = 0
15×2 – 30x – 16x + 32 = 0
15x(x – 2) – 16(x – 2) = 0
x = 16/15 or 2
II.
3y2 – 17y + 24 = 0
3y2 – 9y – 8y + 24 = 0
3y(y – 3) – 8(y – 3) = 0
y = 8/3 or 3
Hence, x < y
