Q. I. x2 – 47x + 480 = 0
II. y = √(31y – 240)
a) x = y or relation cannot be established
b) y> x
c) x ≥ y
d) x ≤ y
e) x> y
Sol:
I.
x2 – 47x + 480 = 0
x2 – 32x – 15x + 480 = 0
x(x – 32) – 15(x – 32) = 0
x = 15 or 32
II.
y = √(31y – 240)
y2 – 31y + 240 = 0
y2 – 15y – 16y + 240 = 0
y(y – 15) – 16(y – 15) = 0
y = 16 or 15
Hence, the relationship between x and y cannot
be established
