The ratio of the number of sweets in three boxes is 3:5:6. If 12 sweets are added to each box, then the new ratio of the sweets in these boxes becomes 19:29:34 respectively. What was the total number of sweets in three boxes initially?
A. 180
B. 210
C. 250
D. 190
E. None of these
Sol:
The number of sweets in three boxes be 3x, 5x
and 6x respectively.
(3x+12 )/( 5x+12) = 19/29
29(3x+12) = 19 (5x+12)
87x+348 = 95x+228
348-228 = 95x-87x
120 = 8x
x=15
Total sweets in three boxes initially = 3x+5x+6x=
14x = 14*15 = 210
