The number 150328 is divisible by 23. If the digits are rearranged in descending order and five times of 13 is subtracted from the new number thus formed, then the resultant number will be divisible by.
(a) 3
(b) 5
(c) 2
(d) 7
Sol:
Here , the number 150328 is divisible by 23
When rearranged in descending order we get = 853210
When 5 times 13 i.e. 65 is subtracted from the new number we get = 853210 -65 = 853145 ⇒ 853145/5 = 170629 .
Hence, the resultant number is divisible by 5 .
