Find the reflection of a point (2, –5) when mirror is placed on y = –2.5?
a) (2, 0)
b) (0, 2)
c) (0.5, –5)
d) (5, –0.5)
Sol:
As shown by figure
Point P = (2, –5) is shown in fourth quadrant is at y = – 2.5
Difference of mirror with P
y = –5 – (–2.5) = –2.5 cm
x remain same as mirror is on y axis hence refection point of P is =
= (2, 0)
