![cos2θ-2sin2θ+2/sin2θ=1 , then what is the value of sin2+ 5cos+ tan2](https://www.gkseries.com/blog/wp-content/uploads/2024/04/cos2θ-2sin2θ2-sin2θ1-then-what-is-the-value-of-sin2-5cos-tan2-.jpg)
cos2θ-2sin2θ+2/sin2θ=1 , then what is the value of sin2+ 5cos+ tan2 .
Sol:
Cos² – 2sin² + 2 = sin² θ
Cos² – sin² – 2sin² + 2 = 0.
1 – 2sin² – 2sin² + 2 = 0.
3 – 4sin² = 0
Sin θ= √3/2
θ =60 °
Put θ=60 °
![](https://www.gkseries.com/blog/wp-content/uploads/2024/04/image-283-1024x340.png)
cos2θ-2sin2θ+2/sin2θ=1 , then what is the value of sin2+ 5cos+ tan2 .
Sol:
Cos² – 2sin² + 2 = sin² θ
Cos² – sin² – 2sin² + 2 = 0.
1 – 2sin² – 2sin² + 2 = 0.
3 – 4sin² = 0
Sin θ= √3/2
θ =60 °
Put θ=60 °
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