cos2θ-2sin2θ+2/sin2θ=1 , then what is the value of sin2+ 5cos+ tan2 .
Sol:
Cos² – 2sin² + 2 = sin² θ
Cos² – sin² – 2sin² + 2 = 0.
1 – 2sin² – 2sin² + 2 = 0.
3 – 4sin² = 0
Sin θ= √3/2
θ =60 °
Put θ=60 °
cos2θ-2sin2θ+2/sin2θ=1 , then what is the value of sin2+ 5cos+ tan2 .
Sol:
Cos² – 2sin² + 2 = sin² θ
Cos² – sin² – 2sin² + 2 = 0.
1 – 2sin² – 2sin² + 2 = 0.
3 – 4sin² = 0
Sin θ= √3/2
θ =60 °
Put θ=60 °