Q. In heat transfer, conductance equals conductivity (kcal/hr/sqm/°C/cm) divided by
A. hr (time)
B. sqm (area)
C. °C (temperature)
D. cm (thickness)
Answer: cm (thickness)
A. hr (time)
B. sqm (area)
C. °C (temperature)
D. cm (thickness)
Answer: cm (thickness)
Government Schemes Mock Test | Start Test! |
Political Science Mock Test – 42 | Start Test |
History Test – 190 | Start Test |
Quantitative Aptitude Test | Start Test! | Data Interpretation - Mock Test | Start Test! |
General Awareness - Mock Test | Start Test! |
Reasoning Ability - Mock Test | Start Test! |