A bowl contains a mixture of oil and water in the ratio of 8: 5. When 78 ml of mixture is taken out and 44 ml of water is added, the ratio of oil and water becomes 1: 2. How much quantity of oil paste does the bowl have initially?
a) 80 ml
b) 100 ml
c) 60 ml
d) 110 ml
Sol:
Let initially the mixture has 8x ml of oil and 5x ml of water paste.
Oil in the bowl = 78 *(8/13) = 48 ml
Water in the bowl = 78 * (5/13) = 30 ml
[8x – 48] / [5x – 30 + 44] = ½
=> 16x – 96 = 5x + 14
=> 11x = 110
=> x = 10
Oil paste initially in the bowl = 8 * 10 = 80 ml
