A container contains 175 liters mixture of acid and water in the ratio of 5:2. If one-fifth of the mixture is taken out and n liters of water is added to the mixture, then the ratio of milk and water becomes 5:3. Find the value of n?
A. 20
B. 35
C. 10
D. 40
E. None of these
Sol:
The quantity of acid in the container = 175 * 5/(5
+ 2) = 175 * 5/7 = 125 liters
The quantity of water in the container = 175 –
125 = 50 liters
1/5th of the quantity of the mixture in the
container = 175/5 = 35 liters
(125 – 35 * 5/(5 + 2))/(50 – 35 * 2/(5 + 2) + n) =
5/3
(125 – 35 * 5/7)/(50 – 35 * 2/7 + n) = 5/3
(125 – 25)/(50 – 10 + n) = 5/3
100 * 3 = 5 * (40 + n)
300 = 200 + 5n
n = 100/5
n = 20
