| Question | A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 am, at what time will he first touch a flag at 120 feet from the ground? | |
| Type | multiple_choice | |
| Option | 4 pm | incorrect |
| Option | 5 pm | incorrect |
| Option | 6 pm | correct |
| Option | None of these | incorrect |
| Solution | Net ascent of the monkey in 1 h = ( 30 – 20 ) feet = 10 feet. So, the monkey ascends 90 feet in 9 h i.e, till 5 pm Clearly , in the next 1 h i.e., till 6 pm the monkey ascends remaining 30 feet to touch the flag. | |
