| Question | A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother? | |
| Type | multiple_choice | |
| Option | 38 years | incorrect |
| Option | 40 years | incorrect |
| Option | 43 years | incorrect |
| Option | 45 years | correct |
| Solution | Let the age of son = X years ∴Age of mother would be =2X As per question 20 years ago; 10 (X -20) = 2X – 20 10X – 200 = 2X – 20 10X – 2X= – 20 + 200 8X = 180 X=180/8= 22.5 years ∴Age of mother = 22.5 * 2 = 45 years | |
