A plane frame shown in the figure (not to scale) has linear elastic springs at node H. The spring constants are kx = ky = 5 × 105 kN/m and kq = 3 × 105 kNm/rad
Q. A plane frame shown in the figure (not to scale) has linear elastic springs at node H. The spring constants are kx = ky = 5 × 105 kN/m and kq = 3 × 105 kNm/rad.
For the externally applied moment of 30 kNm at node F, the rotation (in degrees, round off to 3 decimals) observed in the rotational spring at node H is
Solution:
Since horizontal reaction at E = Hc = 0
Bending moment at F for member FE = MFE = 0
Member FH behaves like propped cantilever beam
30 kNm = 3 × 105 kNm/rad × θ
⇒ θ = 1 × 10-4 radians = 0.0057°