| Question | A storm breaks a tree. The broken part of tree bends so that the top of the tree touches the ground and makes an angle of 60° with the horizontal plane. If the distance between the base of the tree and the point where top of tree touches the ground is 10 m, find the height of the tree? | |
| Type | multiple_choice | |
| Option | 37.3 m | correct |
| Option | 17.3 m | incorrect |
| Option | 27.3 m | incorrect |
| Option | 20.3 m | incorrect |
PQ = 10 and let RQ be X.
X = 10 √3
Now, PR2 = X2 + (10)2
PR2 = (10 √3)2 + (10)2
= 300 + 100
PR2 = 400
PR = 20
Height of tree = RQ + PR
= X + 20
= 10 √3 + 20
= 10 * 1.73 + 20
= 17.3 + 20 = 37.3 meter (Option A)
