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A storm breaks a tree. The broken part of tree bends so that the top of the tree touches the ground and makes an angle of 60° with the horizontal plane. If the distance between the base of the tree and the point where top of tree touches the ground is 10 m, find the height of the tree?

A storm breaks a tree. The broken part of tree bends so that the top of the tree touches the ground and makes an angle of 60° with the horizontal plane. If the distance between the base of the tree and the point where top of tree touches the ground is 10 m, find the height of the tree?
QuestionA storm breaks a tree. The broken part of tree bends so that the top of the tree touches the ground and makes an angle of 60° with the horizontal plane. If the distance between the base of the tree and the point where top of tree touches the ground is 10 m, find the height of the tree?
Typemultiple_choice
Option37.3 mcorrect
Option17.3 mincorrect
Option27.3 mincorrect
Option20.3 mincorrect
Solution

PQ = 10 and let RQ be X.

X = 10 √3

Now, PR2 = X2 + (10)2

PR2 = (10 √3)2 + (10)2

= 300 + 100

PR2 = 400

PR = 20

Height of tree = RQ + PR

= X + 20

= 10 √3 + 20

= 10 * 1.73 + 20

= 17.3 + 20 = 37.3 meter (Option A)

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