A train is running with a speed of (2X – 90) Km/hr while a car is running with a speed of (Y + 30) Km/hr

February 24, 2024

Q. A train is running with a speed of (2X – 90) Km/hr while a car is running with a speed of (Y + 30) Km/hr. If the speed of the train had been equal to that of a car, then it would take 2 hours less to cover 180 km. If the speed of the car had been equal to that of the train, then it would take 3 hours more to cover 270 km. Find the difference between the speed of a bike and a car.

A. 40km/hr

B. 60km/hr

C. 80km/hr

D. 45km/hr

E. Cannot be determined.

Sol:

According to the question,

{180/(2x – 90)} – {180/(y + 30)} = 2

{90/(2x – 90)} – {90/(y +30)} = 1 — (1)

Also, {270/ (2x – 90)} – {270/(y +30)} = 3

(90/ (2x – 90)} – {90/(y + 30)} =1 — (2)

Since both equations are the same.

Therefore, the required difference cannot be determined