A wire would enclose an area of 1936 m2, if it is bent into a square

Q. A wire would enclose an area of 1936 m², if it is bent into a square. The wire is cut into two pieces. The longer piece is thrice as long as the shorter piece. The long and the short pieces are bent into a square and a circle, respectively. Which of the following choices is closest to the sum of the areas enclosed by the two pieces in square meters?

           (A) 1096             (B) 1111                     (C) 1243                     (D) 2486

Ans: 1243

Sol:

Area=1936 m2
a2=1936 m2
a=44 m

Length of wire=4a
=4×44=176 m

Now, Part−1 length
=3×44=132 m

Part−2 length
=1×44=44 m

Long wire is bent in square

So, 4a=132
a=33 m

Area of square=332=1089 m2

Now, small wire is bent into a circle

Total area enclosed

=Area of Square+Area of Circle

=1089+153.94

=1242.97=1243 m2