A wire would enclose an area of 1936 m2, if it is bent into a square
Q. A wire would enclose an area of 1936 m2, if it is bent into a square. The wire is cut into two pieces. The longer piece is thrice as long as the shorter piece. The long and the short pieces are bent into a square and a circle, respectively. Which of the following choices is closest to the sum of the areas enclosed by the two pieces in square meters?
(A) 1096 (B) 1111 (C) 1243 (D) 2486
Ans: 1243
Sol:
Area=1936 m2
a2=1936 m2
a=44 m
Length of wire=4a
=4×44=176 m
Now, Part−1 length
=3×44=132 m
Part−2 length
=1×44=44 m
Long wire is bent in square
So, 4a=132
a=33 m
Area of square=332=1089 m2
Now, small wire is bent into a circle
Total area enclosed
=Area of Square+Area of Circle
=1089+153.94
=1242.97=1243 m2