At the Tripuri session of the Indian National Congress (March 1939), Subhas Chandra Bose defeated

Q. At the Tripuri session of the Indian National Congress (March 1939), Subhas Chandra Bose defeated Mahatma Gandhi’s candidate for Presidentship. Who was he?

(a) Abdul Kalam Azad

(b) V Rajagopalachari

(c) Pattabhi Sitaramayya

(d) Vallabh Bhai Patel

Ans: (c) Pattabhi Sitaramayya

 Explanation: The correct answer is (c) Pattabhi Sitaramayya.

At the Tripuri session of the Indian National Congress held in March 1939, Subhas Chandra Bose defeated Mahatma Gandhi’s candidate for the presidency, Pattabhi Sitaramayya.

Pattabhi Sitaramayya was a prominent freedom fighter and leader within the Indian National Congress. He was nominated by Mahatma Gandhi to contest the presidency against Subhas Chandra Bose. However, Bose’s popularity and his vision for a more radical and aggressive approach to achieving India’s independence resonated with the delegates at the Tripuri session.

As a result, Subhas Chandra Bose emerged victorious in the election, securing the presidency of the Indian National Congress. This marked a significant shift in the direction and leadership of the Congress, as Bose’s presidency signaled a more militant and confrontational stance towards British colonial rule. Therefore, option (c) Pattabhi Sitaramayya is the correct answer.