cos2θ-2sin2θ+2/sin2θ=1 , then what is the value of sin2+ 5cos+ tan2

cos²θ-2sin²θ+2/sin²θ=1 , then what is the value of sin2+ 5cos+ tan2 .

Sol:

Cos² – 2sin² + 2 = sin² θ

Cos² – sin² – 2sin² + 2 = 0.

1 – 2sin² – 2sin² + 2 = 0.

3 – 4sin² = 0

Sin θ= √3/2

θ =60 °

Put θ=60 °