Find the sum of the numbers between 550 and 700 such that when they are divided by 12, 16 and 24, leave remainder 5 in each case.
a) 1998
b) 1887
c) 1788
d) 1884
Sol:
⇒ LCM of 12, 16, and 24 = 48
Multiple of 48 bigger than 550 which leaves remainder 5 are
⇒ 1st Number = 48 x 12 + 5 = 581
⇒ 2nd Number = 48 x 13 + 5 = 629
⇒ 3rd Number = 48 x 14 + 5 = 677
⇒ Sum of these numbers are = 581 + 629 + 677 = 1887
⇒ Hence, The sum of the numbers are 1887.
