Find the value of cot3A-3cotA/3 cot2A-1
(a) cot²2A + tan²A
(b) tan²2A + cot²A
(c) tan3A
(d) cot3A
Sol:
As we know that: tanA + tanB + tanC = tanA tanB tanC
Sin2A + sin2B + sin2C = 4 sinA sinB sinC
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