Q. For any real, square and non-singular matrix B , the det B-1 is
(A) zero
(B) (det B)-1
(C) -(det B)
(D) det B
Ans: (det B)-1
Sol:
For any matrix whose inverse exists i.e. non-singular
BB-1 = I
|BB-1| = 1
|B||B-1| = 1
det (B-1) = (det B)-1