Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?

QuestionFour years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?
Typemultiple_choice
Option34, 9correct
Option33, 7incorrect
Option35, 5incorrect
Option36, 6incorrect
Solution

Let age of son 4 years ago be = X

So, age of man 4 years ago would be = 6X

As per question after 16 years;

2* age of son = age of man

2(X + 4 +16) = (6X + 4 + 16)

2X +40 = 6X + 20

2X – 6X = 20 – 40

– 4X = – 20

X = 5 years

∴Present age of son = 5 + 4= 9 years

Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years

Solution 2:

Apply formula; A’s (man) present age

= 9 years

We will be happy to hear your thoughts

Leave a reply

Gkseries.com
Logo
Register New Account