![Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?](https://www.gkseries.com/blog/wp-content/uploads/2023/07/Four-years-ago-a-man-was-6-times-as-old-as-his-son.-After-16-years-he-will-be-twice-as-old-as-his-son.-What-is-the-present-age-of-man-and-his-son.jpg)
Question | Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son? | |
Type | multiple_choice | |
Option | 34, 9 | correct |
Option | 33, 7 | incorrect |
Option | 35, 5 | incorrect |
Option | 36, 6 | incorrect |
Let age of son 4 years ago be = X
So, age of man 4 years ago would be = 6X
As per question after 16 years;
2* age of son = age of man
2(X + 4 +16) = (6X + 4 + 16)
2X +40 = 6X + 20
2X – 6X = 20 – 40
– 4X = – 20
X = 5 years
∴Present age of son = 5 + 4= 9 years
Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years
Solution 2:
Apply formula; A’s (man) present age
![](https://www.gkseries.com/blog/wp-content/uploads/2023/07/image-69.png)
![](https://www.gkseries.com/blog/wp-content/uploads/2023/07/image-70.png)
![](https://www.gkseries.com/blog/wp-content/uploads/2023/07/image-71.png)
= 9 years