Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?

Question	Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?
Type	multiple_choice
Option	34, 9	correct
Option	33, 7	incorrect
Option	35, 5	incorrect
Option	36, 6	incorrect

Let age of son 4 years ago be = X

So, age of man 4 years ago would be = 6X

As per question after 16 years;

2* age of son = age of man

2(X + 4 +16) = (6X + 4 + 16)

2X +40 = 6X + 20

2X – 6X = 20 – 40

– 4X = – 20

X = 5 years

∴Present age of son = 5 + 4= 9 years

Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years

Solution 2:

Apply formula; A’s (man) present age

= 9 years