Given that √12 = 3.464 and √120 = 10.95, find the value of √1.2 + √1200 + √0.012.
| Question | Given that √12 = 3.464 and √120 = 10.95, find the value of √1.2 + √1200 + √0.012. | |
| Type | multiple_choice | |
| Option | 32.164 | incorrect |
| Option | 35.844 | correct |
| Option | 36.164 | incorrect |
| Option | 37.304 | incorrect |
| Solution | Given exp. = √1.2 +√1200 +√0.0120 = √120/100 +√12*100 + √120/10000 = (√120)/10 + √12 * 10 + (√120)/100 = 10.95/10 + 3.464 * 10 + 10.95/100 = 1.095 + 34.64 + 0.1095 = 35.8445 | |