If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then √a+b+c = ?
(a) 6
(b) 4
(c) 2
(d) 5
Sol:
a + b – c = 5
b + c – a = 9
c + a – b = 7
a + b + c = 25
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