If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then   √a+b+c 

If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then   √a+b+c  = ?

(a)          6

(b)          4

(c)           2

(d)          5

 Sol:

a + b – c = 5

b + c – a = 9

c + a – b = 7

a + b + c = 25