If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

Q. If the 1st ionization energy of H atom is 13.6 eV, then the 2nd ionization energy of He atom is

A.            27.2 eV

B.            40.8 eV

C.            54.4 eV

D.            108.8 eV

Answer: 54.4 eV