Q. In 16-bit 2’s complement representation, the decimal number −28 is:
(A) 1111 1111 0001 1100
(B) 0000 0000 1110 0100
(C) 1111 1111 1110 0100
(D) 1000 0000 1110 0100
Ans: 1111 1111 1110 0100
Solution:
+28 ⇒ 0000 0000 0001 1100 –28 ⇒ 1111 1111 1110 0100 (2’s complement form)
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