Q. In heat transfer, conductance equals conductivity (kcal/hr/sqm/°C/cm) divided by
A. hr (time)
B. sqm (area)
C. °C (temperature)
D. cm (thickness)
Answer: cm (thickness)
A. hr (time)
B. sqm (area)
C. °C (temperature)
D. cm (thickness)
Answer: cm (thickness)