In the figure, PQR is a right angle triangle with angle Q = 90, QR = 17.5 cm and PQ = 42 cm, with PR as a diameter of a semicircle and with QR as radius, a quarter circle is drawn. Find th e area of the shaded portion correct to two decimal places
(a) 3380.125 cm²
(b) 3540.251
(c) 3850.752 cm²
(d) 3284.25
Sol:
Area of shaded portion = area of semicircle of base PR + area of ∆PQR – area of quarter circle of radius
QR
