![In the given figure, ‘ O’ is the centre of circle and AB = BC and ∠AOB = 90°, then ∠a is](https://www.gkseries.com/blog/wp-content/uploads/2024/04/In-the-given-figure-‘-O-is-the-centre-of-circle-and-AB-BC-and-∠AOB-90°-then-∠a-is.jpg)
In the given figure, ‘ O’ is the centre of circle and AB = BC and ∠AOB = 90°, then ∠a is.
![](https://www.gkseries.com/blog/wp-content/uploads/2024/04/image-115-1024x1024.png)
a) 35°
b) 55°
c) 45°
d) 65°
Sol:
![](https://www.gkseries.com/blog/wp-content/uploads/2024/04/image-116-1024x913.png)
∆AOB ∆COB
AB = BC
AO = CO
OB = common
⇒ ∠BOC = 90° as ∠AOB = 90°
⇒ AC = diameter ⇒ ∠ABC = 90°
∠ABO = 45°= ∠a
In the given figure, ‘ O’ is the centre of circle and AB = BC and ∠AOB = 90°, then ∠a is.
a) 35°
b) 55°
c) 45°
d) 65°
Sol:
∆AOB ∆COB
AB = BC
AO = CO
OB = common
⇒ ∠BOC = 90° as ∠AOB = 90°
⇒ AC = diameter ⇒ ∠ABC = 90°
∠ABO = 45°= ∠a
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