Q. “Lobry de Bruyn Alberda Van Ekenstein transformation” is the reaction of
A. Glucose with mild alkali
B. Lactose with enzyme
C. Sucrose with diluted acid
D. Starch with iodine
Answer: Glucose with mild alkali
We will be happy to hear your thoughts
A. Glucose with mild alkali
B. Lactose with enzyme
C. Sucrose with diluted acid
D. Starch with iodine
Answer: Glucose with mild alkali
