Mixture X contains 70% of juice and the remaining water, mixture Y of 64 litres contains juice and water in the ratio of 3:1, if both are mixed in the third container, then the quantity of water in the final mixture is 29.5liters. Find the total volume of Mixture X (in litres)?
A. 40 litres
B. 35 litres
C. 50 litres
D. 60 litres
E. 45 litres
Sol:
Let the initial quantity of mixture X =100x
Amount of juice in the mixture =70% of 100x
=70x
The remaining 30x is water.
Amount of juice in the another mixture = (64/4) ×
3 = 48litres
Remaining 16litres are water.
It is given that,
30x+16 =29.5
30x =13.5
x=0.45
Total quantity of mixture X =100x = 100(0.45) =
45litres
