Find the reflection of a point (2, –5) when mirror is placed on y = –2.5? a) (2, 0) b) (0, 2) c) (0.5, –5) d) (5, –0.5) Sol: As shown by figure Point P = (2, –5) is shown in fourth quadrant is at y = – 2.5 Difference of mirror with P y = –5 – (–2.5) = –2.5 cm x ...
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