A Jar contains 90 litres of the mixture of milk and water in the ratio of 5: 4 and 45 litres of the mixture is taken out. Then added x liters of the water in the remaining mixture, the ratio of the milk and water becomes 2: 3. Find the value of x? A.18 B.17.5 C.16 D.15.5 E.14.5 Sol: Milk = 5/9 ...
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Direction: Find out the wrong number in the following number series. 18, 45, 90, 220, 450 A.450 B.18 C.220 D.45 E. None of these Sol: 18 * 2.5 = 45 45 * 2 = 90 90 * 2.5 = 225 225 * 2 = 450
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The ratio of the length and breadth of the rectangle is 3:2. If the breadth of the rectangle is equal to the side of the square, the radius of the circle is 16.66% more than the length of the rectangle and the area of the circle is 1386m2. Then find the perimeter of the square? ...
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Direction: Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as, Q. I: 5x2 – 18x + 9 = 0 II: 4y2 + 9y - 9 = 0 ...
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Sakshi invested Rs. 30000 in CI at the rate of x % per annum and Rs. 40000 is invested in SI at (x + 5) % rate of interest for one year if she received the total amount at the end of the year is Rs. 75500, then find the rate of interest per annum for Simple interest? A.8 % B.14 % C.10 % D.12 % E. ...
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4/15 of 393 + 7/12 of 473 = ? × (1.99 + 1.01) A.127 B.137 C.157 D.177 E.147 Sol: 4/15 of 393 + 7/12 of 473= ?x (1.99 + 1.01) or, ? x 3 = (4/15) x 393 + (7/12) x 473 or, ? x 3 = (4/15) x390 + (7/12) x 473 or, ? x 3 = 104 + 276 or, ? = 380/3 = 126.667 = 127
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Ragu’s monthly income is 2 times Reena’s monthly income. Reena’s monthly income is 20 % more than Ravi’s monthly income. Reena’s monthly income is Rs. 30000. Find Ragu’s annual income? A.Rs. 680000 B.Rs. 720000 C.Rs. 760000 D.Rs. 640000 E. None of these Sol: Ragu’s monthly ...
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√(2809.001) ÷ 7.98 × (12.01)2 + 46.002 = ? A.1300 B.900 C.1000 D.1100 E.980 Sol: √2809.001 ÷ 7.98 x (12.01)2 + 46.002 = ? or, ? = √2809 ÷ 8 x (12)2 + 46 or, ? = (53/8) x (12)2 + 46 or, ? = 954 + 46 ? = 1000
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(35% of 74000) ÷ ? = (123 % of 13.02)2 ×2.01 A.40 B.50 C.75 D.90 E.65 Sol: (35% of 74000) ÷ ? = (123% of 13.02)2 x 2.01 Or, (35x74000)/ 100 ÷ ? = 2 x 2 or, 25900 / ? = (15.99)2 × 2 or, (25900/?) = 16×16×2 ?= 25900 / (16×16×2) = 50.58 = 50
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17.982 + 4.05 x 90.11 ÷ 4.98 = ? A.396 B.336 C.242 D.423 E.816 Sol: 17.982 + 4.05 x 90.114 ÷ 4.98 = ? 182 + 4 x (90/5) = ? 324 + 4 x 18 =? 324+72 =? ? = 396
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